The normal lines to a given curve at each point pass through `(2,0)`. The curve passes through `(2,3)`. Formulate the differential equation and hence find out the equation of the curve.

The slope of the tangent any point on a curve is lambda times the slope of the joining the point of contact to the origin. Formulate the differential equation and hence find the equation of the curve.

The normal to a given curve at each point (x,y) on the curve passes through the point (3,0) .If the curve contains the point (3,4) find its equation.

The slope of the tangent at any point on a curve is lambda times the slope of the line joining the point of contact to the origin. Formulate the differential equation and hence find the equation of the curve.

A curve passes through the point (0,1) and the gradient at (x,y) on it is y(xy-1) . The equation of the curve is

A curve passes through (1,2) is such that the length of the normal at any of its point is equal to 2. The curve can be

Find the equation of a curve passing through the point (0,0) and whose differential equation is y'=ex sin x

What is the equation of a curve passing through (0, 1) and whose differential equation is given by dy = y tan x dx ?

What is the equation of a curve passing through (0,1) and whose differential equation is given by dy = y tan x dx ?

If the curve satisfying differential equation xdy=(y+x^(3))dx passes through (1, 1), then the equation to the curve is