Water at temperature `100^0C` coos in 10 minutes `80^0C` in a room of temperature `25^0C` . Find The temperature of water after 20 minutes The time when the temperature is `40^0C` [Given: `(log)_e(11)/(15)=-0. 3101 ,log5=1. 6094` ]

Water at temperature 100^@C cools in 10 minutes to 80^@C in a room of temperature 25^@C. Find (i) The temperature of water after 20 minutes (ii) The time when the temperature is 40^@C [Given: (log)_e(11)/(15)=-0. 3101 ,log5=1. 6094 ]

Water at 100^(@) C cools in 10 minutes to 88^(@)C in a room temperature of 25^(@)C .Find the temperature of water after 20 minutes.

A body takes 5 minutes to cool from 75^0 C to 65^0 C . Find the temperature in the next 5 minutes, if the room temperature is 25^0 C .

A body cools in 10 minutes from 60^@C to 40^@C . What will be its temperature after next 10 minutes? The temperature of the surroundings is 10^@C .

At 0^(@)C soil temperature the rate of water absorption

In 5 minutes, a body cools from 75^@C to 65^@C at room temperature of 25^@C . The temperature of body at the end of next 5 minutes is _______ ""^@C .

If 10 g of ice at 0^@C mixes with 10 g of water at 10^@C , then the final temperature t is given by

If 2g ice at 0^(0)C is dropped into 10g water at 80^(0)C then temperature of mixture is

A body cools from "60 ∘ C to 50 ∘C in 10 minutes.If the room temperature is "25 ∘ C then the temperature of the body at the end of the next "10" minutes will be

A body initially at 80^@C cooIs to 64^@C in 5 minutes and to 52^@C in 5 minutes. What will be the temperature after 15 minutes and what is the temperature of surroundings.