`y dx-x dy+y^2cosx dx=0`

Find (dy)/(dx) , when: ytanx-y^(2)cosx+2x=0

An equation of the curve satisfying x dy - y dx = sqrt(x^(2)-y^(2))dx and y(1) = 0 is

The solution of the differential equation dy/dx +y =cosx is -

Find dy/dx if 2x+3y=cosx .

The solution of the differential equation x dx + y dy+ (x dy - y dx)/(x^(2)+y^(2))=0 is

(x(dy)/(dx)-y)e^(y//x)=x^(2)cosx , where v=(y)/(x)

Solution of the differential equation (x(dy)/(dx)-y)e^(y/x)=x^(2)cosx is

Find the order and degree,if defined,of each of the following differential equations: ( i ) (dy)/(dx)-cos x=0 (ii) xy(d^(2)y)/(dx^(2))+x((dy)/(dx))^(2)-y(dy)/(dx)=0 (iii) y''+y^(2)+e^(y')=0