`(1 + xy) ydx + (1-xy)xdy = 0`

Find the particular solutions of : (1+xy)y dx + (1-xy)x dy = 0, y(1)=1 .

The general solution of the differential equation (1+xy)ydx+x(1-xy)dy=0 is

xy log ydx + (1+x^(2)) dy =0

Solve (i) xdx +ydy + (xdy - ydx)/(x^(2) + y^(2)) = 0 (ii) y(1+xy) dx - xdy = 0

The solution of differential equation (1+x)ydx+(1-y)xdy=0 is

The solution of differential equation ydx + (x+xy)dy = 0 is

If the curve satisfying (xy^(4) + y)dx - xdy = 0 passes through (1,1) then the value -41(y(2))^(3) is _______