Evaluate: `intsin^3(theta/2)/(cos(theta/2)sqrt(cos^3theta+cos^2theta+costheta))d theta`

int(costheta-cos2theta)/(1-cos theta)d theta=

costheta-cos2theta=sin3theta

Evaluate int((2 sin theta + sin 2 theta)d theta)/((cos theta-1)sqrt(cos theta + cos^(2) theta + cos^(3) theta)) .

2cos theta-cos3 theta-cos5 theta-16cos^(3)theta sin^(2)theta=

2cos theta-cos3 theta-cos5 theta-16cos^(3)theta sin^(2)theta=

costheta.cos2theta.cos3theta=1/4

Evaluate: int cos2 theta ln((cos theta+sin theta)/(cos theta-sin theta))d theta

sin theta+cos theta=sqrt(3)cos theta then find the value of cos theta-sin theta is

(sin5theta+sin2theta-sin theta)/(cos5theta+2cos3theta+2cos^(2)theta+costheta) is equal to