`inte^(ax)sinbxdx` is:

Evaluate inte^(ax)sinbxdx

Write a value of int e^(ax)sin bxdx

Evaluate: int e^(ax)sin(bx+c)dx

Indefinite Integration | Super Shortcut For JEE Main,BITSAT and NDA | int e^(ax) Sinbx and int e^(ax) cosbx

If u=inte^(ax)sin " bx dx" and v=inte^(ax)cos " bx dx then "(u^(2)+v^(2))(a^(2)+b^(2))=

Evaluate: inte^(ax)cosbxdx

int e^(ax)2^(bx)dx

Evaluate: int e^(ax)cos bxdx

Write a value of int e^(ax)cos bxdx