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int(cos2x-cos2alpha)/(cosx-cosalpha)dx...

`int(cos2x-cos2alpha)/(cosx-cosalpha)dx`

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To solve the integral \[ I = \int \frac{\cos 2x - \cos 2\alpha}{\cos x - \cos \alpha} \, dx, \] we can use trigonometric identities to simplify the expression. ...
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