`int(1+costheta)/(theta+sintheta) d theta`

int (cos2theta) . log((costheta+sintheta)/(costheta-sintheta))d theta is equal to

int(costheta)/(7+sintheta-2cos^2theta)d theta is equal to

Consider a matrix A (theta)= [(sintheta,costheta),(-costheta,sintheta)] then

The value of int(1+sin2theta)/(sintheta-costheta)d""theta is equal to

If (1+ sintheta-costheta)/(1+ sintheta + costheta)+(1+sintheta+costheta)/(1+sintheta-costheta)= 4 , then which of the following values will be suitable for theta ?

(sintheta)/(1+costheta) + (1+costheta)/(sintheta) = 2 cosec theta

int((sintheta+costheta))/sqrt(sin2theta)"d"theta=

Prove that int_0^(pi/2)(costheta-sintheta)/(1+sintheta.costheta)d theta=0.

Simplify: cos theta[{:(costheta,sintheta),(-sintheta,costheta):}]+sintheta[{:(sin theta ,-costheta),(costheta, sintheta):}]