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`intcos(blog(x/a))dx`

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intcos(logx)/xdx

The integral intcos(log_(e)x)dx is equal to: (where C is a constant of integration)

Knowledge Check

  • intcos(logx)dx=F(x)+c , where c is an arbitrary constant. Here F(x)=

    A
    `x[cos(logx)+sin(logx)]`
    B
    `x[cos(logx)-sin(logx)]`
    C
    `x/2[cos(logx)+sin(logx)]`
    D
    `x/2[cos(logx)-sin(logx)]`

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