The line `y=m x` bisects the area enclosed by the curve `y=1+4x-x^2` and the lines `x=0,x=3/2a n dy=0.` Then the value of `m` is `(13)/6` b. `6/(13)` c. `3/2` d. `4`

The line y=mx bisects the area enclosed by the curve y=1+4x-x^(2) and the lines x=0,x=(3)/(2) and y=0. Then the value of m is (A) (13)/(6) (B) (6)/(13)(C)(3)/(2) (D) 4

Determine the area enclosed by the curve y=x^3 , and the lines y=0,x=2 and x = 4.

What is the area enclosed between the curve y^(2)=12x and the lines x=0 and y=6?

The area bounded by the curve y^(2) = 4x and the line 2x-3y+4=0 is

What is the area enclosed between the curves y^(2) = 12x and the lines x= 0 and y= 6 ?

Area enclosed by the curve y = sin^(2)x , the X-axis and the lines x=0, x=pi//2 is

The area bounded by the curve x^(2)=4y+4 and line 3x+4y=0 is

The area enclosed between the curve y^(2)(2a-x)=x^(3) and the line x=2 above the x-axis is

Area enclosed by the curve x^(2)y=36 , the X-axis and the lines x = 6 and x = 9, is