The area enclosed by the circle `x^2+(y+2)^2=16` is divided into two parts by the x-axis. Find by integration, the area of the smaller part.

Find the area enclosed by the circle x^(2)+y^(2)=25

The circle x^(2)+y^(2) =4a^(2) is divided into two parts by the line x =(3a)/(2). Find the ratio of areas of these two parts.

Find the area enclosed by the circle x ^(2) +y ^(2) =9.

Find the area enclosed by the circle x^(2)+y^(2)=a^(2)

Find the area of the circle x ^(2) + y ^(2) = 16

Smaller area enclosed by the circle x^(2)+y^(2)=4 and line x+y=2 is

The line 3x+2y=13 divides the area enclosed by the curve,9x^(2)+4y^(2)-18x-16y-11=0 into two parts,Find the ratio of the larger area to smaller area

The area between the curve x=y^(2) and x=4 which divide into two equal parts by the line x=a. Find the value of a

Smaller area enclosed by the circle x^(2)+y^(2)=a^(2) and the line x+y=a is

The area enclosed between the curve y^(2)(2a-x)=x^(3) and the line x=2 above the x-axis is