The area formed by triangular shaped region bounded by the curves `y=sinx, y=cosx` and `x=0` is (A) `sqrt(2)-1` (B) `1` (C) `sqrt(2)` (D) `1+sqrt(2)`

The area of the figure bounded by the curves y=cosx and y=sinx and the ordinates x=0 and x=pi/4 is (A) sqrt(2)-1 (B) sqrt(2)+1 (C) 1/sqrt(2)(sqrt(2)-1) (D) 1/sqrt(2)

Find the area of the region bounded by the curves 2y^2=x, 3y^2=x+1, y=0 .

The area of the region bounded by the lines x=0, x=pi/2 and f(x)=sinx, g(x)=cosx is (A) 2(sqrt(2)+1) (B) sqrt(3)-1 (C) 2(sqrt(3)-1) (D) 2(sqrt(2)-1)

The area of the region bounded by curves y=1-x^(2), x+y+1=0 and x-y-1=0 is

The area of the region bounded by the curves y=|x-2| , x=1, x=3 and the x-axis is (A) 3 (B) 2 (C) 1 (D) 4

The area bounded by the curves y=|x|-1 and y=-|x|+1 is a.1b.2c2sqrt(2)d.4

The area under the curve y=|cosx-sinx|, 0 le x le pi/2 , and above x-axis is: (A) 2sqrt(2)+2 (B) 0 (C) 2sqrt(2)-2 (D) 2sqrt(2)