The area of the figure bounded by the curves `y=cosx` and `y=sinx` and the ordinates `x=0` and `x=pi/4` is (A) `sqrt(2)-1` (B) `sqrt(2)+1` (C) `1/sqrt(2)(sqrt(2)-1)` (D) `1/sqrt(2)`

The area bounded by the curve y=secx , the x-axis and the lines x=0 and x=pi/4 is (A) log(sqrt(2)+1) (B) log(sqrt(2)-1) (C) 1/2log2 (D) sqrt(2)

Find the area of the region bounded by the curves y=sqrt(x+2) and y=(1)/(x+1) between the lines x=0 and x=2.

The area bounded by the curves y""=""cos""x""a n d""y""="sin""x between the ordinates x""=""0""a n d""x""=(3pi)/2 is (1) 4sqrt(2)+""2 (2) 4sqrt(2)""1 (3) 4sqrt(2)+""1 (4) 4sqrt(2)""2

The area bounded by the y-axis, y" "=" "cos" "x and y" "=" "s in" "x when 0lt=xlt=pi/2 is (A) 2(sqrt(2-1)) (B) sqrt(2)-1 (C) sqrt(2)+1 (D) sqrt(2)

The area formed by triangular shaped region bounded by the curves y=sinx, y=cosx and x=0 is (A) sqrt(2)-1 (B) 1 (C) sqrt(2) (D) 1+sqrt(2)

The area enclosed by the curves y=sin x+cos x and y=|cos x-sin x| over the interval [0,(pi)/(2)] is (a) 4(sqrt(2)-1) (b) 2sqrt(2)(sqrt(2)-1)(c)2(sqrt(2)+1)(d)2sqrt(2)(sqrt(2)+1)

The area enclosed by the curve y=sin x+cos x and y=|cos x-sin x| over the interval [0,(pi)/(2)] is 4(sqrt(2)-2) (b) 2sqrt(2)(sqrt(2)-1)2(sqrt(2)+1)(d)2sqrt(2)(sqrt(2)+1)

The area of the region bounded by the lines x=0, x=pi/2 and f(x)=sinx, g(x)=cosx is (A) 2(sqrt(2)+1) (B) sqrt(3)-1 (C) 2(sqrt(3)-1) (D) 2(sqrt(2)-1)

The area bounded by the curves y=|x|-1 and y=-|x|+1 is a.1b.2c2sqrt(2)d.4

If A is the area bounded by the curves y=sqrt(1-x^(2)) and y=x^(3)-x, then of (pi)/(A)