The area bounded by the curve `y=secx`, the x-axis and the lines `x=0` and `x=pi/4` is (A) `log(sqrt(2)+1)` (B) `log(sqrt(2)-1)` (C) `1/2log2` (D) `sqrt(2)`

The area bounded by the curve y = log x, X- axis and the ordinates x = 1, x = 2 is

The area of the figure bounded by the curves y=cosx and y=sinx and the ordinates x=0 and x=pi/4 is (A) sqrt(2)-1 (B) sqrt(2)+1 (C) 1/sqrt(2)(sqrt(2)-1) (D) 1/sqrt(2)

The area bounded by the curve y=2^(x), the x- axis and the left of y-axis is (A) log _(e)2(B)log_(e)4 (C) log_(4)e(D)log_(2)e

Find the area bounded by the curves y=x+sqrt(x^(2)) and xy=1, the x -axis and the line x=2

The area bounded by the curves y=|x|-1 and y=-|x|+1 is a.1b.2c2sqrt(2)d.4

Area lying between the curves y=tanx, y=cotx and x-axis, x in [0, pi/2] is (A) 1/2log2 (B) log2 (C) 2log(1/sqrt(2)) (D) none of these

The area bounded by y=sec^(-1)x,y=cos ec^(-1)x, and line x-1=0 is (a)log(3+2sqrt(2))-(pi)/(2) sq.units (b) (pi)/(2)-log(3+2sqrt(2)) sq.units (c)pi-(log)_(e)3 sq.units (d) non of these

The function f is such that : f(xy)=f(x)+f(y), x, y gt 0 and f\'(1)=2 and A the area bounded by the curves y=f(x), x=2 and the x-axis, then (A) f(x)=2log_ex (B) f(x)=2 log_ex (C) A=2(2log_e2-1) (D) A=4log(2/sqrt(e))

Differentiate log((x+sqrt(x^(2)-1))/(x-sqrt(x^(2)-1)))