The area enclosed between the curves `y=ax^2 and x=ay^2(a > 0)` is 1 sq. unit, value of a is `1/sqrt3` (b) `1/2` (c) 1 (d) `1/3`

The area enclosed between the curves y=ax^(2) and x=ay^(2)(a>0) is 1 sq.unit, value of a is (1)/(sqrt(3)) (b) (1)/(2)(c)1(d)(1)/(3)

If the area enclosed between the curves y=ax^(2) and x=ay^(2)(a>0) is 1 square unit, then find the value of a.

If the area enclosed between the curves y=kx^(2) and x=ky^(2), where k>0, is 1 square unit.Then k is: (a) (1)/(sqrt(3)) (b) (sqrt(3))/(2) (c) (2)/(sqrt(3))(d)sqrt(3)

The area bounded by the curves y=ax^(2) .and x=ay^(2) is equal to 1 then a=(a>0)

The area enclosed between the curves y^(2)=x and y=|x| is (1)2/3(2)1(3)1/6(4)1/3

Compute the area enclosed by the curve y^(2)= (1-x^(2))^(3)