Let `f(x)=min.[tanx, cotx, 1/sqrt(3)], x in [0, pi/2]`. If the area bounded by `y=f(x)` and x-axis is `ln(a/b)+pi/(6sqrt(3))`, where `a,b` are coprimes. Then `ab`=…..

Let f(x)=min[tan x,cot x,1sqrt(3)] for all x in(0,(pi)/(2)) Then the area bounded by y=f (x) and the X -axis is

Let f(x) = minimum (tan x, cot x, 1//sqrt(3) ) AA x in [0, pi//2] . Then area bounded by y = f(x) and the x-axis is log ((a)/(b)) + (pi)/(c sqrt(d)) , then a + b - c + d = _______

Let f(x) = minimum (x+1, sqrt(1-x))" for all "x le 1. Then the area bounded by y=f(x) and the x-"axis" is

Let f(x)= minimum (x+1,sqrt(1-x) for all x<=1 then the area bounded by y=f(x) and the x -axis,is

If f(x)=max{sin x,cos x,(1)/(2)}, then the area of the region bounded by the curves y=f(x), x-axis,Y-axis and x=(5 pi)/(3) is

Let f(x)="max"{sin x,cos x,1/2} , then determine the area of region bounded by the curves y=f(x) , X-axis, Y-axis and x=2pi .

Find the area bounded by y= sec^(2) x , x = pi/6, x = pi/ 3 & x-axis