Solve the differential equation `(x^2+4y^2+4xy)dy=(2x+4y+1)dx`

AI Generated Solution

Similar Questions

Explore conceptually related problems

Solve the differential equation (y^2+x^2)dx=(x^2+xy)dy

Solve the differential equation (x ^(2) - yx ^(2) ) dy + (y ^(2) + xy ^(2)) dx = 0

Solve the differential equations x^(2)dy-(x^(2)+xy-2y^(2))dx=0

Solve the differential equation (dy)/(dx)=1-x+y-xy

Solve the following differential equation (x^2+xy)dy=(x^2+y^2)dx

Solve the following differential equations (x^2-y^2)dx+2xy""dy=0, y(1)=1 .

The solution of the differential equation (2x^(2) +2 y^(2))dx- 4xy dy= 0 is

Solve the differential equation (x+2y^(2))(dy)/(dx)=y, given that when x=2,y=1

Solve the differential equation : (dy)/(dx)=(x^(2)-y^(2))/(xy) .

Solve the differential equation, (a^(2))/(xy).(dx)/(dy)=(x)/(y)+(y)/(x)-2, is