`ysinx dy/dx=(sinx-y^2)cosx`

(dy)/(dx)=2(sinx-cosx)^(-2)

Find y(pi) if y(0)=7 and (dy)/dx=2(y-2sinx-10)x+2cosx

"If "y=(sinx)^(cosx)+(cosx)^(sinx)", prove that "(dy)/(dx)=(sinx)^(cosx).[cot x cos x-sin x(log sinx)]+(cosx)^(sinx).[cosx(log cos x)-sinx tanx].

(dy)/(dx)tany=sinx+cosx

If y=e^(sinx)+(tanx)^(x)," prove that "(dy)/(dx)=e^(sinx)cosx+(tanx)^(x)[2x" cosec "2x+log tanx].

Solve: (2+sinx)/(1+y) (dy)/(dx)=-cosx