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The solution of the equation (e^x+1)ydy+...

The solution of the equation `(e^x+1)ydy+(y+1)dx=0`, is (A) `e^(x+y)=C(y+1)e^x` (B) `e^(x+y)=C(x+1)(y+1)` (C) `e^(x+y)=C(y+1)(1+e^x)` (D) `e^(xy)=C(x+y)(e^x+1)`

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