A tangent drawn to the curve `y=f(x)` at `P(x,y)` cuts the x-axis and y-axis at `A` and `B` respectively such that `BP:AP=2:1`. Given that `f(1)=1`. Answer the question:Equation of normal to curve at `(1,1)` is (A) `x-4y+3=0` (B) `x-3y+2=0` (C) `x-2y+1=0` (D) none of these

A tangent drawn to the curve y=f(x) at P(x,y) cuts the x-axis and y-axis at A and B respectively such that BP:AP=2:1 . Given that f(1)=1 . Answer the question:Equation of curve is (A) y=1/x (B) y=1/x^2 (C) y=1/x^3 (D) none of these

A tangent drawn to the curve y=f(x) at P(x,y) cuts the x-axis and y-axis at A and B respectively such that BP:AP=2:1 . Given that f(1)=1 . Answer the question:The curve passes through the point (A) (2,1/4) (B) (2,1/2) (C) (2,1/8) (D) none of these

A tangent drawn to the curve y = f(x) at P(x, y) cuts the x and y axes at A and B, respectively, such that AP : PB = 1 : 3. If f(1) = 1 then the curve passes through (k,(1)/(8)) where k is

The normal to the curve x^(2)=4y passing (1,2) is (A) x+y=3 (B) x-y=3 (D) x-y=1

Tangent is drawn at any point P of a curve which passes through (1,1) cutting x -axis and y -axis at A and B respectively.If AP:BP=3:1, then

The equation of the tangent to the curve y=sec x at the point (0,1) is (a) y=0 (b) x=0 (c) y=1 (d) x=1

The equation of normal to the curve x^(2)+y^(2)-3x-y+2=0 at P(1,1) is

The equation of normal to the curve y=2x^(3)-x^(2)+2 at ((1)/(2),2) is a) 2x-4y+7=0 b) 2x+y-3=0 c) x+y=0 d). 2x-y+3=0

A curve y=f(x) passes through (1,1) and tangent at P(x , y) cuts the x-axis and y-axis at A and B , respectively, such that B P : A P=3, then (a) equation of curve is x y^(prime)-3y=0 (b) normal at (1,1) is x+3y=4 (c) curve passes through 2, 8 (d) equation of curve is x y^(prime)+3y=0