if `(1+3+5-...upto n terms)/(4+7+10+...upto n terms)=20/(7log_10 X` and `n = log_10 x + log_10 X^1/2 + log_10 X^1/4 + ............ + oo` , then `x` is equal to

if (1+3+5-...up rarr nterms)/(4+7+10+...up rarr nterms)=(20)/(7log_(10)X) and n=log_(10)x+(log_(10)X^(1))/(2)+(log_(10)X^(1))/(4)+.........+oo then x is equal to

If (1 + 3 + 5 + .... " upto n terms ")/(4 + 7 + 10 + ... " upto n terms") = (20)/(7 " log"_(10)x) and n = log_(10)x + log_(10) x^((1)/(2)) + log_(10) x^((1)/(4)) + log_(10) x^((1)/(8)) + ... + oo , then x is equal to

If (1+3+5+...+ nterms )/(4+7+10+... nterms )=(20)/(7log_(10)x) and n=log_(10)x+log_(10)x^((1)/(2))+.......oo then x is equal to

Given that log_10 2 =x, log_10 3 =y then log_10 1.2=

Solve x+log_10(2^x+1)= log_10 6+xlog_10 5 .

If log_(10) 2, log_(10)(2^(x) -1) , log_(10)(2^(x)+3) are in AP, then what is x equal to?

Solve for x. log_(0.1) sin 2x +log_10 cos x = log_10 7 .

If the sum of the first 20 terms of the series log_((7^(1//2)))x + log_((7^(1//3))) x + log_((7^(1//4)))x + .... is 460 , then x is equal to :

What is log_10(3/2)+log_10 (4/3)+log_10 (5/4)+………. up to 8 terms equal to