prove that `log2 + 16 log(16/15) + 12 log(25/24) + 7 log(81/80) = 1 `

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prove that log2+16log((16)/(15))+12log((25)/(24))+7log((81)/(80))=1

Prove that log2+16(log16)/(15)+12(log25)/(24)+7(log81)/(80)=1

Find the value of 7 log(16/15) + 5 log (25/24) + 3 log (81/80) .

7 log (10)/(9) + 3 log""(81)/(80) =

The value of 7log((16)/(15))+5log((25)/(24))+3log((81)/(80))=