if `x =log_a (bc), y= log_b (ca) and z=log_c(ab)` then `1/(x+1)+1/(y+1)+1/(z+1)`

if =log_(a)(bc),y=log_(b)(ca) and z=log_(c)(ab) then (1)/(x+1)+(1)/(y+1)+(1)/(z+1)

If x=log_(a)(bc),y=log_(b)(ca),z=log_(c)(ab) then (1)/(x+1)+(1)/(y+1)+(1)/(z+1) is equal to

If x = log_(a) bc, y = log_(b) ca, z = log_(c) ab, then the value of (1)/(1 + x) + (1)/(1 + y) + (1)/(l + z) will be

If x=log_(a)(bc),y=log_(b)(ca)" and "z=log_(c)(ab) , then which of the following is equal to 1 ?

If x ="log"_(a)(bc), y ="log"_(b)(ca) " and "z = "log"_(c)(ab), then which of the following is correct?

If x=1+log_(a) bc, y=1+log_(b) ca, z=1+log_(c) ab , then (xyz)/(xy+yz+zx) is equal to

If x = 1 + log_(a) bc, y = 1 + log_(b) ca, z = 1 + log_(c) ab, then xy + yz + zx =

If log_(a)bc = x, log_(b)ca = y and log_(c)ab = z , then the value of (1)/(x +1) + (1)/(y +1) + (1)/(z+1) is equal to