Find the number of digits in `(72)^15` without actual computation. Given `log2=0.301, log3=0.477.`

What is the number of digits in 7^(25), 8^(23) , and 9^(20) respectively ? [Given log_10 2 = 0.301, log_10 3 = 0.477, log_10 7 = 0.845 ]

Let S denotes the antilog of 0.5 to the base 256 and K denotes the number of digits in 6^(10) (given log_(10)2=0.301 , log_(10)3=0.477 ) and G denotes the number of positive integers, which have the characteristic 2, when the base of logarithm is 3. The value of SKG is

Find the number of digits in 3^(81)xx5^(57), if log_(10)3=0.4771 and log_(10)5=0.6990

If log2=0.30103, find the number of digits in 2^(56).

If log2=0.30103 , find the number of digits in 2^(56)

Number of significant digits in 2^(20) times 3^(5) is ( log_(10)2 =0.30 , log_(10)3 =0.4771 ).