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Show that: 1/(log2n)+1/(nog3n)+1/(log4n)...

Show that: `1/(log_2n)+1/(nog_3n)+1/(log_4n)+…+1/(log_43n)=1/(log_43n)

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If n in N, prove that 1/(log_2x)+1/(log_3x)+1/(log_4x)++(1)/(log_n x)=1/(log_(n !)x)

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