For `xgt1`, show that: `2log_10x-log_x 0.01ge4`

solve for x:2log_(10)x-log_(x)(0.01)=5

For x>1, the minimum value of 2log_(10)(x)-log_(x)(0.01) is

The least value of the expression 2(log)_(10)x-(log)_(x)(0.01)* for x>1 is (a) 10 (b) 2(c)-0.01(d)4

The least value of the expression 2(log)_(10)x-(log)_(x)(0.01), for x>1, is (1980,2M)(a)10(b)2(c)-0.01(d) None of

The least value of the expression 2(log)_(10)x-(log)_x(0. 01),forx >1, is a. 10 b. 2 c. -0.01 d. none of these

If 0

If xgt0 prove that x+ 1/x ge2