Prove that `sintheta+s in3theta+sin5theta++sin(2n-1)theta=(sin^2ntheta)/(sintheta)dot`

Prove that sin theta+sin3 theta+sin5 theta+....+sin(2n-1)theta=(sin^(2)n theta)/(sin theta)

sintheta+sin7theta=sin4theta

Prove that, sintheta+sin2theta+sin3theta+ . . .sinntheta=(sin""(ntheta)/(2)"sin"(n+1)/(2)theta)/("sin"(theta)/(2)) for all ninN .

Slove : sin9theta =sintheta

Solve 4sintheta sin2thetasin4theta=sin3theta

Prove that :(sin theta+2sin3 theta+sin5 theta)/(sin3 theta+2sin5 theta+sin7 theta)=(sin3 theta)/(sin5 theta)

(sin theta+2sin3 theta+sin5 theta)/(sin3 theta+2sin5 theta+sin7 theta)=(sin3 theta)/(sin5 theta)

(sin theta+2sin3 theta+sin5 theta)/(sin3 theta+2sin5 theta+sin7 theta)=(sin3 theta)/(sin5 theta)

Prove that : (sintheta-costheta)/(sintheta+costheta)+(sintheta+costheta)/(sintheta-costheta)=(2)/(2sin^(2)theta-1)

The value of sintheta + sin3theta +sin5theta + "….."+ sin(2n-1)theta is