`sin 36^o sin 72^o sin 108^o sin 144^o =`

sin 36^(º)sin 72^(º) sin108^(º) sin 144^(º) =

sin36^(@)sin72^(@)sin108^(@)sin144^(@)=

sin36^(@)sin72^(@)sin108^(@)sin144^(@)=

sin36^(@)sin72^(@)sin108^(@)sin144^(@)=(5)/(16)

Prove that: "sin"(pi)/(5)"sin"(2pi)/(5)"sin"(3pi)/(5)"sin"(4pi)/(5)=(5)/(16) "sin"36^(@) "sin"72^(@) "sin"108^(@) sin 144^(@)=(5)/(16) .

sin36^(@).sin72^(@).sin108^(@).sin144^(@)=?

Prove that: sin36^(@)s in72^(0)s in108^(0)s in144^(0)=(5)/(16)