If `tan(pi/4+theta/2)=tan^3(pi/4+alpha/2)` then `sin(theta)=(sin(alpha)(3+sin^2(alpha)))/(1+3sin^2(alpha))`

tan((pi)/(4)+alpha)=(1+sin2 alpha)/(cos2 alpha)

If tan^(3) (alpha/2+ pi/4) = tan(beta/2 +pi/4) then prove that sin beta = ((3 + sin^(2)alpja) sin alpha) /(1 + 3sin^(2)alpha)

Show that 4sin alpha*sin(alpha+(pi)/(3))sin(alpha+2(pi)/(3))=sin3 alpha

If tan (alpha+theta)=n tan (alpha-theta) ,show that: (n+1)"sin" 2theta=(n-1) sin 2alpha

sin alpha+sin(alpha+((2pi)/3))+sin(alpha+((4pi)/3))=0

tan theta = (sin alpha-cos alpha) / (sin alpha + cos alpha)

If tan theta=(sin alpha- cos alpha)/(sin alpha+cos alpha) , then

(1-2sin^(2)alpha)/(1+sin2 alpha)=(1-tan alpha)/(1+tan alpha)

(1-2sin^(2)alpha)/(1+sin2 alpha)=(1-tan alpha)/(1+tan alpha)

prove that 4sin alpha*sin(alpha+(pi)/(3))*sin(alpha+(2 pi)/(3))=sin3 alpha