If `tantheta+tan(theta+pi/3)+tan(theta-pi/3)=ktan3theta` then k is equal to

tan theta+tan(theta+(pi)/(3))+tan(theta-(pi)/(3))=k tan36 then k is equal to

If tan theta + tan (pi/3 +theta) + tan (frac{2pi}{3}+ theta) = k tan 3theta then k is equal to

tantheta+tan2theta=tan3theta

tan theta tan((pi)/(3)+theta)tan((pi)/(3)-theta)=tan3 theta

If theta=(pi)/(12) then the value of tan^(6)theta+3tan^(4)theta-64tan^(3)theta+3tan^(2)theta+25 is equal to