If `sinx, cosx, tanx`are in G.P., then `cot^6x-cot^2x=` (A) 0 (B) -1 (C) 1 (D) depends on x

If A=f(x)=[(cosx, sinx, 0),(-sinx, cosx,0),(0,0,1)], then the value of A^-1= (A) f(x) (B) -f(x) (C) f(-x) (D) -f(-x)

The value of cot(tan^(-1)2x+cot^(-1)2x) is ... (A) 0 (B) 2x (C) 4x (D) pi+2x A B C D

Let f(x)=|cosx x 1 2sinx x2xsinx x x| , then (lim)_(x->0)(f(x))/(x^2) is equal to (a) 0 (b) -1 (c) 2 (d) 3

If sin alpha,sin beta and cos alpha are in G.P then roots of x^(2)+2x cot beta+1=0 are always

If in a ABC,tan A+tan B+tan C=0 then cot A cot B cot C=6b.1c*(1)/(6)d .none of these

Show that cot 2x cot x - cot 3x cot 2x -cot x=1

Evaluate cot (tan^(-1) (2x) + cot^(-1) (2x))

int(sin^3x+cos^3x)/(sin^2xcos^2x)dx (A) sinx+cosx+c (B) tanx+cotx+c (C) secx-cosecx+c (D) sinx-cosx+c

cot^(-1)((1+cosx)/(sinx))