If any `triangle ABC, tanA+tanB+tanC=6` and `tanAtanB=2`, then the values of `tanA, tanB` and `tanC` are respectively` (A) 1,2,3 (B) 3,2,1 (C) 2,1,3 (D) 1,2,0

In triangle A B C ,tanA+tanB+tanC=6a n dtanAtanB=2, then the values of tanA ,tanB ,tanC are, respectively (a)1,2,3 (b) 3,2//3,7//3 (c)4,1//2 ,3//2 (d) none of these

In a triangle ABC, tanA+tanB+tanC=6 and tanA. tan B = 3, then find the nature of triangle.

In a triangle ABC tanA+tanB+tanC>=P then P=

In DeltaABC, if tanA+tanB+tanC=6 and tanA.tanB=2 then tanC= . .

If, in a triangleABC , tanA =1 and tanB=2, then: tanC=

In an acute-angled triangle ABC, tanA+tanB+tanC

If cos(A-B) = 3/5 and tanA.tanB=2, then

If angles A and B satisfy (1+tanA)(1+tanB)=2 , then the value of A +B is

In any triangle ABC , (tanA/2-tanB/2)/(tanA/2+tanB/2) is equal to

Find the value of tanA+tanB+tanC , if A+B+C=pi :