The sides of a triangle are `x^2+x+1, 2x+1 and x^2-1.` Prove that the greatest angle is `120^0`

If the measures of the sides of triangle are (x^2 - 1), (x^2 + 1) and 2x cm, then the triangle would be

If the sides of a triangle are in the ratio x:y:sqrt(x^(2)+xy+y^(2)) ,then the greatest angle is

If the equations of three sides of a triangle are x+y=1, 3x + 5y = 2 and x - y = 0 then the orthocentre of the triangle lies on the line/lines

if length of the sides of a Delta ABC are x^(2)+x+1,2x+1,x^(2)-1 then half of the largest angle of a Delta ABC is

If the sides of a triangle are in A.P., and its greatest angle exceeds the least angle by alpha , show that the sides are in the ration 1+x :1:1-x , , where x = sqrt((1- cos alpha)/(7 - cos alpha))

If the sides of a triangle are x, y and sqrt((x^(2) + xy + y^(2))) , then then measure of its greatest angle is....

The equations of the three sides of a triangle are x=2,y+1=0 and x+2y=4 .The coordinates of the circumcentre of the triangle are

The measure of sides are (x^(2)-1), (x^(2)+1) and 2x cm. then the triangle is-