If the sides of triangle `ABC` are in G.P with common ratio `r (r<1)`, show that `r<1/2(sqrt5+1)`

The sides of a triangle ABC are in GP.Ifr is the common ratio then r lies in the interval

If three successive terms of G.P from the sides of a triangle then show that common ratio ' r' satisfies the inequality 1/2 (sqrt(5)-1) lt r lt 1/2 (sqrt(5)+1) .

Sides of triangle ABC, a, b, c are in G.P. If 'r' be the common ratio of this G.P. , then

Three successive terms of a G.P. will form the sides of a triangle if the common ratio r satisfies the inequality

if (a,b),(c,d),(e,f) are the vertices of a triangle such that a,c,e are in GP .with common ratio r and b,d,f are in GP with common ratio s, then the area of the triangle is

If pth, qth, rth terms of an A.P. are in G.P. then common ratio of ths G.P. is (A) (q-r)/(p-q) (B) (q-s)/(p-r) (C) (r-s)/(q-r) (D) q/p

The sides of a triangle ABC are in A.P.and its area is 1/3rd of an equilateral triangle of same perimeter.Find ratio of the sides of triangle.

If the sides of a triangle are in G.P.,and its largest angle is twice the smallest,then the common ratio r satisfies the inequality 0