`1/(bc)+1/(ca)+1/(ab)=`

The vertices of a triangle are (ab,(1)/(ab)),(bc,(1)/(bc)),(ca,(1)/(ca)) where a,b,c are roots of the equation x^(3)-3x^(2)+6x+1=0 then centroid is

If a,b,are positive then which of the following holds good?(A) b^(c)-2+c^(2)a^(2)+a^(2)b^(2)>=abc(a+b+c)(B)(bc)/(a)+(ca)/(b)+(ab)/(c)>=a+b+c((C)(bc)/(a^(3))+c(a)/(b^(3))+a(b)/(c^(3))>=(1)/(a)+(1)/(b)+(1)/(c)(D)(1)/(a)+(1)/(b)+(1)/(c)>=(1)/(sqrt(bc))+(1)/(sqrt(ca))+(1)/(sqrt(ab)))

If a,b,c are in A.P then a+(1)/(bc),b+(1)/(ca),c+(1)/(ab) are in

If a,b,c are in A.P. prove that: (i) (ab)^(-1),(ca)^(-1) and (bc)^(-1) are also in A.P. (ii) (ab+ac)/(bc),(bc+ca)/(ca),(ca+cb)/(ab) are also in A.P.

Prove that (1)/(a) + (1)/(b) + (1)/(c ) ge (1)/(sqrt((bc))) + (1)/(sqrt((ca))) + (1)/(sqrt((ab))) , where a,b,c gt 0

If a,b,c are in A.P., then (bc)/(ca+ab),(ca)/(bc+ab),(ab)/(bc+ca)

What is 1/(bc(a-b)(a-c)) + 1/(ca(b-c)(b-a)) + 1/(ab(c-a)(c-b)) equal to?