In an acute-angled triangle ABC, `tanA+tanB+tanC`

In an acute angled triangle ABC, let AD,BE and CF be the perpendicular opposite sides of the triangle.The ratio of the product of the side lengths of the triangles DEF and ABC, is equal to

In an acute angled triangle ABC,if (tan A)/(2)=(tan B)/(3)=(tan C)/(5) then /_ABC is equal to

Assertion : Delta ABC is an acute angled triangle, angle A, angle B and angle C are less than 90^(@) Reason : Triangles are classified according to the sides and the angles.

Naming triangles by considering the measures of their angles acute triangle A triangle whose all the angles are acute is called an acute- angled triangle or an acute triangle.

Statement-1: In an acute angled triangle minimum value of tan alpha + tanbeta + tan gamma is 3sqrt(3) . And Statement-2: If a,b,c are three positive real numbers then (a+b+c)/3 ge sqrt(abc) into in a triangleABC , tanA+ tanB + tanC= tanA. tanB.tanC

If in a triangle ABC, (tanA)/1= (tanB)/2 = (tanC)/3 then prove that 6sqrt(2a)=3sqrt(5b)=2sqrt(10)c

In a triangle ABC tanA+tanB+tanC>=P then P=

In a triangle ABC, tanA + tanB + tanC = 9. If tan^2 A+ tan^2 B + tan^2 C= k then the least value of k^(9/7) is

In right angled triangle ABC, right angled at C, show that tanA+tanB=(c^2)/(ab) .