The number of triangles `ABC` that can be formed with `sinA=5/(13), a=3` and `b=8` is

The number of triangles ABC that can be formed with sin A=(5)/(13),a=3 and b=8 is

A triangle ABC in which side AB,BC,CA consist 5,3,6 points respectively, then the number of triangle that can be formed by these points are

In triangleABC , if a=13, b=14, c=15 , then sinA=

If A(5,-1),B(-3,-2) and (-1,8) are the vertices of triangle ABC,find the length of median through A and the coordinates of the centroid.

In any triangle ABC, the side are a=7,b=5 and c=8. Find A.

In triangle ABC , prove that a^2sin(B-C)=(b^2-c^2)sinA .

In a triangle ABC ,if the centroid is (2,0) and the mid point of BC is (1,3) then A=

Let A(3,4) B(5,0), C(0,5) be the vertices of a triangle ABC then orthocentre of Delta ABC is (alpha, beta) Find alpha + beta