If the base angles of triangle are `(22)/(12)a n d112 1/2^0` , then prove that the altitude of the triangle is equal to `1/2` of its base.

If the base angles of triangle are ((22)/(12))^(@) and (112(1)/(2))^(@), then prove that the altitude of the triangle is equal to (1)/(2) of its base.

If the base angles of a triangle are 22(1)/(2),112(1)/(2) then third angle is

If the area of triangle with base 12 cm is equal to the area of a square with side 12 cm, then the altitude of the triangle is:

If the bisectors of the base angles of a triangle enclose an angle of 135^(0) ,prove that the triangle is a right triangle.

If the bisectors of the base angles of a triangle enclose an angle of 135^(0) ,prove that the triangle is a right triangle.

If the area of a triangle is 1176 cm^(2) and base : corresponding altitude is 3:4, then the altitude of the triangle is:

If the area of an isosceles triangle is sqrt(2)+1 and vertical angle is 45^(@) then the base of the triangle is

If the orthocenter of an isosceles triangle lies on the incircle of the triangle then A) the base angle of the triangle is cos^-1 2/3 B) the triangle is acute C) the base angle of the triangle is tan^-1 (sqrt5/2) D) If S, I are the circumcentre and incentre and R is circumradius then SI/R=1/3