If the sides of a quadrilateral ABCD touch a circle prove that
`AB+CD=BC+AD.`

If the sides of a quadrilateral ABCD touch a circle and AB = 6 cm, CD = 5 cm, BC = 7 cm, then the length of AD in cm is :

If the sides of a quadrilateral ABCD touch a circle and AB = 6 cm, CD = 5 cm BC = 7 cm, then the length of AD (in cm) is

A quadrilateral ABCD is drawn to circumscribe a circle.Prove that AB+CD=AD+BC

A circle touches all the four sides of a quadrilateral ABCD.Prove that AB+CD=BC+DA

A circle touches all the four sides of a quadrilateral ABCD .Prove that: AB+CD=BC+DA

If four sides of a quadrilateral ABCD are tangential to a circle,then AC+AD=BD+CD(b)AB+CD=BC+AD(c)AB+CD=AC+BC(d)AC+AD=BC+DB

In Figure, a quadrilateral ABCD is drawn to circumscribe a circle . Prove that AB+CD=BC+AD

In cyclic quadrilateral ABCD, AD|| BC. Prove that AB = CD.