If a circle is inscribed in right angled triangle ABC with right angle at B, show that the diameter of the circle is equal to `AB+BC-AC.`

In right angled triangle ABC, right angled at C, show that tanA+tanB=(c^2)/(ab) .

ABC is a right angled triangle AB = 3 cm, BC = 5 cm and AC = 4 cm, then the inradius of the circle is :

ABC is a right angled triangle AB = 3 cm, BC = 5 cm and AC = 4 cm, then the inradius of the circle is :

A circle is inscribed in a right angled triangle of perimeter 7pi . Then the ratio of numerical values of circumference of the circle to the area of the right angled triangle is :

A circle is inscribed in a right triangle ABC, right angled at C. The circle is tangent to the segment AB at D and length of segments AD and DB are 7 and 13 respectively. Find the area of triangle ABC.

1.In a right angled triangle ABC,AB=AC Thena:b: c is

ABC is a right-angled triangled, right angled at A*AD is drawn perpendicular to BC from A . Then AB^2 is equal to

ABC is a isosceles right angled triangle, right angled at C. prove that AB^(2) = 2AC^(2)