Let `P Qa n dR S` be tangent at the extremities of the diameter `P R` of a circle of radius `rdot` If `P Sa n dR Q` intersect at a point `X` on the circumference of the circle, then prove that `2r=sqrt(P Q x R S)` .

Let PQ and RS be tangent at the extremities of the diameter PR of a circle of radius r. If P S and RQ intersect at a point X on the circumference of the circle,then prove that 2r=sqrt(PQ xx RS).

Let PQ and RS be tangents at the extremities of the diameter PR of a circle of radius r. If PS and RQ intersect at a point X on the circumference of the circle,then 2r equals

Let PQ and RS be tangents at the extremities of the diameter PR of a circle of radius r. PS and RQ intersect at a point X on the circumference of the circle. If PQ = 9 and RS = 4, then the diameter of the circle is :

Tangents to a circle at points P and Q on the circle intersect at a point R. If PQ= 6 and PR= 5 then the radius of the circle is

In the figure, two circles intersect each other in points P and Q. If tangent from point R touch the circles at S and T, then prove that RS=RT.

P, Q, R and S are the points on the circumference of a circle of radius r, such that PQR is an equilateral triangle and PS is a diameter of circle. What is the perimeter of the quadrilateral PQSR?

P,Q,S and R are points on the circumference of a circle of radius r ,such that POR is an equilateral triangle and PS is a diameter of the circle.What is the perimeter of the quadrilateral PQSR?

P Q R S is a square such that P R\ a n d\ S Q intersect at Odot State the measure of /_P O Q