One angle of an isosceles triangle is `120^0` and the radius of its incricel is `sqrt(3)dot` Then the area of the triangle in sq. units is `7+12sqrt(3)` (b) `12-7sqrt(3)` `12+7sqrt(3)` (d) `4pi`

One angle of an isosceles triangle is 120^(@) and the radius of its incricel is sqrt(3) .Then the area of the triangle in sq.units is 7+12sqrt(3)(b)12-7sqrt(3)12+7sqrt(3)(d)4 pi

Given an isosceles triangle,whose one angle is-2(pi)/(3) and the radius of its incircle =sqrt3 Then find the area of the triangle

The length of a median of an equilateral triangle is 12sqrt(3) cms. Then the area of the triangle is :

Two medians drawn from the acute angles of a right angled triangle intersect at an angle (pi)/(6) . If the length of the hypotenuse of the triangle is 3 units,then the area of the triangle (in sq. units is (a) sqrt(3)(b)3(c)sqrt(2) (d) 9

sqrt(3)sqrt(4)sqrt(12)=

sqrt(2)x^(2)+7sqrt(2)x+12sqrt(3)=0