Home
Class 12
MATHS
The equation (cosp-1)^x^2+(cos p)x+s in ...

The equation `(cosp-1)^x^2+(cos p)x+s in p=0` in the variable `x` has real roots. The `p` can take any value in the interval `(0,2pi)` (b) `(-pi)` (c) `(-pi/2,pi/2)` (d) `(,pi)`

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation (cos p-1)x^(2)+(cos p)x+sin p=0 in the variable x has real roots.The p can take any value in the interval (a) ( 0,2 pi)( b) (-pi,0) (c) (-(pi)/(2),(pi)/(2))( d )(0,pi)

The equation (cos p-1) x^(2) + cos p*x + sin p = 0 where x is a variable, has real roots. Then the interval of possible values of p is

The equation (cos p-1)x^(2)+cos p*x+sin p=0 in x has real roots.Then the set of values of p is (a) [0,2pi](b)[-pi,0](c)[-(pi)/(2),(pi)/(2)](d)[0,pi]

One of the root equation cos x-x+(1)/(2)=0 lies in the interval (0,(pi)/(2))(b)(-(pi)/(2,0))(c)((pi)/(2),pi)(d)(pi,(3 pi)/(2))

f(x) = cos x is strictly increasing in the interval : (a) ((pi)/(2),pi) (b) (pi,(3 pi)/(2)) (c) (0,(pi)/(2))