The number of values of `theta` in the interval `(-pi/2,pi/2)` such that `theta != npi/5` for `ninN` and `tan theta = cot 5theta` as well as `sin2theta = cos 4theta` is

The number of values of theta in the interval (-(pi)/(2), (pi)/(2)) such that theta ne (n pi)/(5) " for n" = 0, +-1, +-2 " and tan" theta = "cot"5theta " as well as sin" 2 theta = "cos" 4theta , is

The number of values of theta in the interval [-(pi)/(2),(pi)/(2)] and theta!=(n pi)/(5) is where n=0,+-1,+-2 and tan theta=cot(5 theta) and sin(2 theta)=cos(4 theta) is

tan (pi cos theta) = cot (pi sin theta)

The number of solutions of tan(5 pi cos theta)=cot(5 pi sin theta) for theta in[0,pi]

If tan2theta = cot(theta - 18^(@)) , then the value of sin(5theta)/4 + cos (5theta)/4 is:

The number of solutions of cot(5pi sin theta )=tan (5 pi cos theta ), AA theta in (0,2pi) is

Prove that (tan 5theta + tan 3theta)/(tan 5theta - tan 3theta) = 4 cos 2theta cos 4theta

If 5 tan theta =4, find the value of (5 sin theta - 3 cos theta)/(5 sin theta +2 cos theta)