`sin^-1(sin 5)> x^2-4 x` holds if

sin^(-1)(sin5)>x^(2)-4x holds if

"sin"^(-1)("sin" 5)>x^2-4x holds if

sin^(-1)(sin5)>x^(2)-4x hold if (a)x=2-sqrt(9-2 pi)(b)x=2+sqrt(9-2 pi)(c)x>2+sqrt(9-2 pi)(d)x in(2-sqrt(9-2 pi),2+sqrt(9-2 pi))

If sin^-1(sin 5)gtx^(2)-4x then

solve sin^(-1) (sin 5) gt x^(2) - 4x

The set of vlues of x for which tan^(-1)(x)/sqrt(1-x^(2))=sin^(-1) x holds is

The number of all possible 5-tuples (a_(1),a_(2),a_(3),a_(4),a_(5)) such that a_(1)+a_(2) sin x+a_(3) cos x + a_(4) sin 2x +a_(5) cos 2 x =0 hold for all x is