Find the sum `tan^-1 (1/(3+3.1+1^2))+tan^-1 (1/(3+3.2+2^2))+…+tan^-1 (1/(3+3n+n^2))`

Find the sum tan^-1 (x/ (1+1.2x^2))+tan^-1 (x/(1+2.3x^2))+…+tan^-1 (x/(1+n(n+1)x^2)) xgt0

Sum to n terms the series tan^-1 (1/(1+1+1^2))+tan^-1 (1/(1+2+2^2))+tan^-1 (1/(1+3+3^2))+…

Sum the series tan^-1 (x/(1+1*2x^1))+tan^-1 (x/(1+2*3x^2))+…+tan^-1 (x/(1+n*(n+1)x^2))

Sum the following series to infinity : tan^(-1)(1/(1+1+1^2))+tan^(-1)(1/(1+2+2^2))+tan^(-1)(1/(1+3+3^2))+.................

Evaluate tan^(-1).(1)/(2)+ tan^(-1).(1)/(3) .

2tan^(-1)((1)/(3))+tan^(-1)((1)/(2))=

tan ^ (- 1) ((1) / (2)) + tan ^ (- 1) ((1) / (3))

Show by mathematical induction that tan^(-1) .(1)/(3) + tan^(-1). (1)/(7) + …+tan^(-1). (1)/(n^2 + n +1)= tan^(-1). (n)/(n+2), AA n inN .

Sum the following series to infinity: (tan^(-1)1)/(1+1+1^(2))+(tan^(-1)1)/(1+2+2^(2))+(tan^(-1)1)/(1+3+3^(2))+