Find the sum oif the series `sintheta- (sin2theta)/(2!)+(sin3theta)/(3!)-… to oo`

Find the sum of the series costheta- (cos2theta)/(2!)+(cos3theta)/(3!)-… to oo

Solve: sin3theta=sin2theta

2sin^(2)theta-3sintheta=-1 :find theta

Solve 4sintheta sin2thetasin4theta=sin3theta

Prove that sin theta sec3 theta=(1)/(2)[tan3 theta-tan theta] and hence find the sum to n terms of the series sin theta sec3 theta+sin3 theta sec3^(2)theta+sin3^(2)theta sec3^(3)theta+...

Sum ot n terms the series sin^3theta+sin^3 3theta+sin^3 5 theta+…

Find the sum to n terms of the series sin^3 theta +1/3 sin^3 3theta+1/3^2sin^3 9theta+1/3^3 sin^3 27theta+…

Sum to terms of the series sin theta sin2 theta+sin2 theta sin3 theta+sin3 theta sin4 theta+... is equal to

Find the sum of n terms of the series sqrt(1-sin2theta)+(sqrt(1-sin4theta)+sqrt(1-sin6theta)+…

Find ( sin theta - sin 3 theta )/( sin^(2) theta - cos^(2) theta)