Sum ot n terms the series `sin^3theta+sin^3 3theta+sin^3 5 theta+…`

sin theta + sin3 theta + sin5 theta = 0

Prove that sin theta sec3 theta=(1)/(2)[tan3 theta-tan theta] and hence find the sum to n terms of the series sin theta sec3 theta+sin3 theta sec3^(2)theta+sin3^(2)theta sec3^(3)theta+...

Find the sum to n terms of the series sin^3 theta +1/3 sin^3 3theta+1/3^2sin^3 9theta+1/3^3 sin^3 27theta+…

Sum to terms of the series sin theta sin2 theta+sin2 theta sin3 theta+sin3 theta sin4 theta+... is equal to

Sum to n terms the series costheta-sin2theta-cos3theta+sin4theta+cos5theta-……

Find the sum oif the series sintheta- (sin2theta)/(2!)+(sin3theta)/(3!)-… to oo

If sin theta=(3)/(5), then sin3 theta=

Find the sum of n terms of the series sqrt(1-sin2theta)+(sqrt(1-sin4theta)+sqrt(1-sin6theta)+…

Let f(theta)=sin theta(sin theta+sin3 theta)* then

The number of values of theta satisfying the equation sin theta+sin5 theta=sin3 theta such that theta in[0,pi] is