Sum to n terms the series `costheta-sin2theta-cos3theta+sin4theta+cos5theta-……`

costheta-cos2theta=sin3theta

Sum to terms of the series sin theta sin2 theta+sin2 theta sin3 theta+sin3 theta sin4 theta+... is equal to

Sum ot n terms the series sin^3theta+sin^3 3theta+sin^3 5 theta+…

Find the sum of the series costheta.cos2theta+cos3theta.cos4theta+cos5theta.cos6theta+…to n terms

Find the sum of n terms the series: 1/(costheta+cos3theta)+1/(costheta+cos5theta)+1/(costheta+cos7theta)+…

Solve: sin2theta+sin4theta=costheta+cos3theta

if theta=(pi)/(6) then the 10 th term of the series 1+(cos theta+i sin theta)^(1)+(cos theta+i sin theta)^(2)+

cos theta-cos3 theta+cos5 theta-cos7 theta=4sin theta sin4 theta cos2 theta

If theta=7.5^(@) Find the value of quad sin8 theta*cos theta-sin6 theta cos3 thetacos2 theta*cos theta-sin3 theta*sin4 theta

If theta=(pi)/(6) then the 10^(th) term of the series : 1+(cos theta+i sin theta)^(1)+(cos theta+i sin theta)^(2)+