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(tanA)/(1-cotA)+(cotA)/(1-tanA)=secA cos...

`(tanA)/(1-cotA)+(cotA)/(1-tanA)=secA cosec A+1`

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Prove that : (tanA)/(1-cotA)+(cotA)/(1-tanA)=1+secA" cosec"A

If (tanA)/(1-cotA)+(cotA)/(1-tanA)=K+tanA+cotA then K = ?

If (tanA)/(1-cotA)+(cotA)/(1-tanA)=K+tanA+cotA, then K = ?

Prove that (tanA)/((1-cotA))+(cotA)/((1-tanA))=(1+tanA+cotA).

The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as :

The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as

The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as (1) s e c A""cos e c A""+""1 (2) t a n A""+""cot A (3) s e c A""+""cos e c A (4) s in A""cos A""+""1

(tanA)/(1+secA) - (tanA)/(1-secA) = 2cosecA